Help 1

23 1/4

(3/6)^2+7*4-5

9/36+7*4-5

1/4+28-5

1/4+23

23 1/4

$(\frac{3}{6})^2+7*4-5\\ =(\frac{1}{2})^2+28-5\\ =(\frac{1^2}{2^2})+28-5\\ =\frac{1}{4}+28-5\\ =28-5+\frac{1}{4}\\ =23+\frac{1}{2}\\ =23\frac{1}{4}\\$