+69 \(\frac{z^2-4}{z-3}/\frac{z+2}{z^2+z-12}\)
Switch the division sign to multiplication and switch the top and bottom equations on the second fraction.
\(\frac{z^2-4}{z-3}*\frac{z^2+z-12}{z+2}\)
Simplify the polynomial
\(\frac{(z+2)(z-2)}{z-3}*\frac{(z+4)(z-3)}{z+2}\)
You can cross out from top to bottom, top left to bottom right, and bottom left to top right.
\((z-2)(z+4)\)
Multiply your answer.
\(z^2-2z-8\)
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To find out the restrictions, you need to take the bottom number of each fraction and make it equal to zero.
\(z-3=0\)
\(z=3\)
...
\(z^2+z-12=0\)
\((z+4)(z-3)=0\)
\(z+4=0, z-3=0\)
\(z=-4, z=3\)
You can't use -4 or 3 as an answer to this problem.
