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Help 29,30

 May 15, 2018
 #1
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29.

 

We want to permute   all possible orders of selecting any 3 students from 10....so we have

 

P (10,3)   = 720 ways

 

 

30.

 

We have 36 possible outcomes.....the ones that sum to 6  are

 

1,5

5,1

4,2

2,4

3,3    =     5 ways

 

So...the probabilitiy  is     5 / 36

 

 

 

cool cool cool

 May 15, 2018

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