Help 29,30 ​

29.

We want to permute   all possible orders of selecting any 3 students from 10....so we have

P (10,3)   = 720 ways

30.

We have 36 possible outcomes.....the ones that sum to 6  are

1,5

5,1

4,2

2,4

3,3    =     5 ways

So...the probabilitiy  is     5 / 36