Help 3 ​

6.

There is discontinuity at any x value that causes a zero in the denominator.

 

There is discontinuity when...

 

x + 9  =  0       and       x + 7  =  0

x  =  -9            and       x  =  -7

 

7.

Since  (x + 1)  is in the denominator but not in the numerator, there is an asymptote at   x  =  -1

Since  (x + 4)  is in the denominator and in the numerator, there is a hole at   x  =  -4