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Help 3

 Feb 20, 2018

Best Answer 

 #1
avatar+7354 
+2

6.

There is discontinuity at any x value that causes a zero in the denominator.

 

There is discontinuity when...

 

x + 9  =  0       and       x + 7  =  0

x  =  -9            and       x  =  -7

 

7.

Since  (x + 1)  is in the denominator but not in the numerator, there is an asymptote at   x  =  -1

Since  (x + 4)  is in the denominator and in the numerator, there is a hole at   x  =  -4

 Feb 21, 2018
 #1
avatar+7354 
+2
Best Answer

6.

There is discontinuity at any x value that causes a zero in the denominator.

 

There is discontinuity when...

 

x + 9  =  0       and       x + 7  =  0

x  =  -9            and       x  =  -7

 

7.

Since  (x + 1)  is in the denominator but not in the numerator, there is an asymptote at   x  =  -1

Since  (x + 4)  is in the denominator and in the numerator, there is a hole at   x  =  -4

hectictar Feb 21, 2018

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