Help 44,45 ​

45. tan 5pi/6=\(\frac{-\sqrt3}{3}\)

44.

We  have this function

y  = A cos (Bθ )

A  = the amplitude = l 0.5  l   = 0.5

To find B....we have that

2pi  / period  = B

2pi / [ 2 pi / 3 ]  = B

2pi * 3  / 2pi  = B 

3  = B

So...the correct answer is

y  = 0.5cos (3θ )