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Help 50

 May 17, 2018
 #1
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2sin x   cos x  + √3 cos x  = 0        factor out  cos x

 

cos x  (2 sinx + √3 )   = 0

 

Set each factor to 0 and solve for x

 

cos x  = 0    and this happens at   x = pi/2  and 3pi/2

 

2sinx + √3  =  0     subtract  √3 from both sides

 

2 sin x  = -√3       divide both sides by 2

 

sin x  = -√3 / 2     and this happens at  4pi/3 and  5pi/3

 

So...the correct answer is

 

pi/2, 4pi/3, 3pi/2, 5pi/3

 

 

cool cool cool

 May 18, 2018

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