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Help 6 

NotSoSmart  Feb 20, 2018

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 #1
avatar+7056 
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\(0.12\,=\,\frac{100(0.05)+x(0.2)}{100+x} \\~\\ 0.12(100+x)\,=\,100(0.05)+x(0.2) \\~\\ 12+0.12x\,=\,5+0.2x \\~\\ 12-5=0.2x-0.12x \\~\\ 7\,=\,0.08x \\~\\ 87.5=x\)

 

the amount of  20% dye to add  is  87.5 mL .

hectictar  Feb 21, 2018
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 #1
avatar+7056 
+2
Best Answer

\(0.12\,=\,\frac{100(0.05)+x(0.2)}{100+x} \\~\\ 0.12(100+x)\,=\,100(0.05)+x(0.2) \\~\\ 12+0.12x\,=\,5+0.2x \\~\\ 12-5=0.2x-0.12x \\~\\ 7\,=\,0.08x \\~\\ 87.5=x\)

 

the amount of  20% dye to add  is  87.5 mL .

hectictar  Feb 21, 2018

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