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Please Help 

 

 Apr 12, 2019
 #1
avatar+111456 
+1

Part A - I believe that net A is the correct one

 

Part B  -   AB  = 3 in     BC = 5 in   CD = 4 in

 

Part C -  Surface Area

 

We have two right triangles with leg of 3 and 4

So....their areas =  2(1/2)(product of leg lengths) =  3 * 4 =  12 in^2

 

Base  is a   4 * 8.6  rectangle =  34.4 in^2

 

Top is a  5 * 8.6 rectangle = 43 in^2

 

Back is a 3 * 8.6 rectangle = 25.8 in^2

 

So....the total surface area  =  12 + 8.6 (3 + 4 +  5)  = 12 + 8.6(12) = 12 (1 + 8.6) = 12 * 9.6   = 115.2 in^2

 

 

cool cool cool

 Apr 12, 2019
 #2
avatar+1014 
-4

Thanks 

Nickolas  Apr 12, 2019

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