+129907 Part A - I believe that net A is the correct one
Part B - AB = 3 in BC = 5 in CD = 4 in
Part C - Surface Area
We have two right triangles with leg of 3 and 4
So....their areas = 2(1/2)(product of leg lengths) = 3 * 4 = 12 in^2
Base is a 4 * 8.6 rectangle = 34.4 in^2
Top is a 5 * 8.6 rectangle = 43 in^2
Back is a 3 * 8.6 rectangle = 25.8 in^2
So....the total surface area = 12 + 8.6 (3 + 4 + 5) = 12 + 8.6(12) = 12 (1 + 8.6) = 12 * 9.6 = 115.2 in^2
