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Mean = [ 6(1) + 3(2) + 2(3) + 1(4) + 1(10) ] / 13 ≈ 2.46
Sorting the data in ascending order
1,1,1,1,1,1,2,2,2,3,3,4,10
Median = 2
It appears that the median is a better measure because the data is skewed to the left and there is an outlier