+129845 Let's use a little analyses, NSS
Note that when x = 0 .......y is positiive (-12/ -25 ) = 12/25 which is < 1
So....this rules out the second graph and the third graph
Note that we can find out where the graph is = 0 by solving this
x^2 + 5x - 12 = 0
x^2 + 5x + 25/4 = 12 + 25/4
(x + 5/2)^2 = 73/4 take both roots
x + 5/2 = ±√73 / 2
x = √73 / 2 - 5/2 ≈ 1.77
x = -√73 / 2 - 5/2 ≈ -6.77
Notice that the 4th graph appears to have "zeroes" at about these values
Let's confirm that the 4th graph is correct :
https://www.desmos.com/calculator/rfpfjuqtrb
