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Help 9

NotSoSmart  Mar 6, 2018
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3+0 Answers

 #1
avatar+86528 
0

No graphs shown , NSS .....sad sad sad

 

 

 

cool cool cool

CPhill  Mar 6, 2018
 #2
avatar+2482 
0

Sorry here they are

NotSoSmart  Mar 6, 2018
 #3
avatar+86528 
+2

Let's use a little analyses, NSS

 

Note that when x  = 0   .......y  is positiive  (-12/ -25 )  = 12/25   which is  < 1

So....this rules out the second graph and the third graph

 

Note that we can  find out where the graph is  = 0  by solving this

 

x^2 + 5x  - 12  = 0 

x^2 + 5x + 25/4  =  12 + 25/4

(x + 5/2)^2  =  73/4       take both roots

 

x + 5/2  =  ±√73 / 2

 

x  =  √73 / 2  -  5/2  ≈  1.77

x  = -√73 / 2  - 5/2   ≈ -6.77 

 

Notice that the 4th graph appears to have "zeroes" at about these values

 

 

Let's confirm that the 4th graph is correct :

 

https://www.desmos.com/calculator/rfpfjuqtrb

 

 

cool cool cool

CPhill  Mar 6, 2018

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