x= -3 -x^2+6x-4 HALP ;-;
x= -3 -x^2+6x-4
\(x= -3 -x^2+6x-4 \\ 0= -3 -x^2+5x-4 \\ 0= -x^2+5x-7 \\ 0= x^2-5x+7 \\ \triangle=b^2-4ac=25-28=-3\\ since\;\;\triangle<0\;\;\text{there are no real solutions}\\~\\ \text{Note that the triangle is called the discriminant} \)
you can just say the awnser is undefinable
