If y>0, find the range of all possible values of y such that \(\lceil{y}\rceil\cdot\lfloor{y}\rfloor=42 \). Express your answer using interval notation.
If \(y>0\), find the range of all possible values of \(y\) such that \(\lceil{y}\rceil\cdot\lfloor{y}\rfloor=42.\)
\lceil{y}\rceil\cdot\lfloor{y}\rfloor=42.
Express your answer using interval notation.
\(6 \lt y \lt 7\)
Source:
Mathematica 11 Home Edition gives the following 2 values: solve ceiling({y}) floor({y}) = 42 for y
-7 < y < -6 and 6 < y < 7
Thanks, guys!
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