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A sequence \(T_n\) is given as: \(T_{1}=7;T_{2}=13;T_{3}=19;T_{4}=25\) such that the difference between every two consecutive terms is the ​same.

Find the value of \(T_{1}+T_{2}+T_{3}+\cdots+T_{50}\).

 Jan 9, 2021
 #1
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T50  = T1  +  6(50-1)   =   7 + 6*49    = 301

 

Sum  = 

 

(first term + last term)  (number of terms)/ 2   =

 

(7 + 301)  (50) / 2   =

 

(308) * 25    = 

 

7700

 

 

cool cool cool

 Jan 10, 2021

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