+0  
 
0
113
2
avatar+187 

Solve for all solutions 0-2pi

 

1) Sin2xSinx-Cos2xCosx= -cosx

2) Sec^2x = 4tan^2x

3) cos(pi-x) +sin(x-pi/2) = 1

8) 2cos^2x=1

Maplesnowy  May 31, 2018
 #1
avatar+13014 
+2

1

sin^2x sinx = -cos x + cos^2x cosx    ( I will drop the 'x' for easier typing)

                      = -cos ( 1- cos^2)

   sin^2 sin     =   -cos (sin^2)

   sin = - cos

    x = 3pi / 4    and   7pi/4

ElectricPavlov  May 31, 2018
 #2
avatar+13014 
+2

8)

2 cos^2 = 1

cos^2 = 1/2

cos = +- sqrt (1/2) = +-.707       pi/4   3pi/4   5pi/4   7pi/4

ElectricPavlov  May 31, 2018

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