For specific positive numbers m and n, the quadratics 16x^2+56x+36 and (mx+n)^2 differ only in their constant term. What is mn?
16x^2 + 56x + 36
Let m = 4, n = 7
Note : 56 = 2 (4)(7)
(4x + 7)^2 = (4x + 7) ( 4x + 7) = 16x^2 + 56x + 49
mn = 4 * 7 = 28
