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When given the quadratic equation with integer roots: mx^2 - (m-2)x + m - 8 = 0 

What's the value of integer parameter m? And what are the integer roots?

 Jan 7, 2021
 #1
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We can apply the quadratic formula:

 \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

$a=m$

$b=-(m-2)$

$c=(m-8)$

 

x =\({(m-2) \pm \sqrt{(-m+2)^2-4m(m-8)} \over 2m}\)

can you take it from here?

 Jan 7, 2021

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