When given the quadratic equation with integer roots: mx^2 - (m-2)x + m - 8 = 0
What's the value of integer parameter m? And what are the integer roots?
We can apply the quadratic formula:
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
$a=m$
$b=-(m-2)$
$c=(m-8)$
x =\({(m-2) \pm \sqrt{(-m+2)^2-4m(m-8)} \over 2m}\)
can you take it from here?