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The height of an object is given by h = -16t^2 + 137t + 100
Find the two points in time when the object is 148 feet above the ground . Round your answer to the nearest hundredth of a second (two decimal places)

 Jul 25, 2021
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h = 148

 

148 = -16t^2+137t+100     

 

-16t^2 +137t -48  = 0    Use Quadrtatic Formula to find the two values of 't'       a = -16     b = 137    c = -48

 

\(t = {-137 \pm \sqrt{137^2-4(-16)(-48)} \over 2(-16)}\)        compute on !

 Jul 25, 2021

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