The height of an object is given by h = -16t^2 + 137t + 100
Find the two points in time when the object is 148 feet above the ground . Round your answer to the nearest hundredth of a second (two decimal places)
+36915 h = 148
148 = -16t^2+137t+100
-16t^2 +137t -48 = 0 Use Quadrtatic Formula to find the two values of 't' a = -16 b = 137 c = -48
\(t = {-137 \pm \sqrt{137^2-4(-16)(-48)} \over 2(-16)}\) compute on !
