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# help algebra

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Let f(x)=3x^2  - 4x - x^2 + 7x + 8. Find the constant k such that f(x)=f(k-x) for all real numbers x.

Aug 1, 2021

#1
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Let f(x)=3x^2  - 4x - x^2 + 7x + 8. Find the constant k such that f(x)=f(k-x) for all real numbers x.

Hello Guest!

$$f(x)=3x^2 - 4x - x^2 + 7x + 8=f(k-x)$$

$$k\in \mathbb R\ |\ 6\leq k<\infty$$

!

Aug 1, 2021