When f(x) = ax^3 - 6x^2 + bx - 5 is divided by x - 1, the remainder is 5. When f(x) is divided by x - 2, the remainder is -53. Find the ordered pair (a,b).
+37159 (not sure of this)
when divided by (x-1) r = 5 sub in x = 1
a (1^3) -6(1^2)+ b(1) - 5 = 5
a + b = 16 or b = 16- a
when divided by (x-2) r = - 53 sub in x = 2
8a -24 +2b-5 = - 53
8a + 2b = - 24 sub in red equation for 'b'
8a + 2 ( 16-a) = - 24
6a = - 56
a = -9.333 then b = 16-a = 25.333
Here is a graph I used to verify:
https://www.desmos.com/calculator/e2svzjdotb
