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If the roots of the quadratic equation 1/2*x^2 + 99x + c = 0 are x = -99 + sqrt(8021) and x = -99 - sqrt(8021), then what is the value of c?

 Feb 16, 2022
 #1
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(992 - sqrt(8201)2)/2 = 890

 Feb 16, 2022
 #2
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....because from Vieta     R1 R2  =   c / a  

 

R1 R1 = c / ( 1/2)  = 2c

 

R1R2 / 2 = c  

 

(-99 + sqrt (8201) (-99 + sqrt (8201) / 2  =  ( 99^2 - 8201 ) / 2 = 890

Guest Feb 16, 2022
 #3
avatar+36417 
+1

*** edited ***    Fixed typo    answer is the same

 

....because from Vieta     R1 R2  =   c / a  

 

R1 R2 = c / ( 1/2)  = 2c

 

R1R2 / 2 = c  

 

(-99 + sqrt (8201) (-99 + sqrt (8201) / 2  =  ( 99^2 - 8201 ) / 2 = 890

ElectricPavlov  Feb 16, 2022

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