The roots of Ax^2+Bx+1 are the same as the roots of x^2- 3x + 5 + x^2 - 2x + 1. What is A+B?
-1/2
x^2+x^2-3x-2x+5+1=2x^2-5x+6
we divide that by six so the constant term is the same:1
(2x^2-5x+6)/6=1/3x^2-5/6x+1
so now we know A=1/3, B=-5/6
A+B=1/3-5/6=-1/2
+1733 
