If the two roots of the quadratic 7x^2 + 3x + k = 0 are $\frac{-3 \pm i \sqrt{271}}{14}$, what is k?
Using the quadratic formula, we obtain that the two solutions are $\frac{-3 \pm i\sqrt{4(7)(k)-9}}{14}$, so we have:
$4(7)(k)-9=271$
$28k-9=271$
$28k=280$
$\boxed{k=10}$
Using the quadratic formula, we obtain that the two solutions are $\frac{-3 \pm i\sqrt{4(7)(k)-9}}{14}$, so we have:
$4(7)(k)-9=271$
$28k-9=271$
$28k=280$
$\boxed{k=10}$