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If the two roots of the quadratic 7x^2 + 3x + k = 0 are $\frac{-3 \pm i \sqrt{271}}{14}$, what is k?

 Apr 6, 2021

Best Answer 

 #1
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Using the quadratic formula, we obtain that the two solutions are $\frac{-3 \pm i\sqrt{4(7)(k)-9}}{14}$, so we have:

 

$4(7)(k)-9=271$

$28k-9=271$

$28k=280$

$\boxed{k=10}$

 Apr 6, 2021
 #1
avatar+485 
+2
Best Answer

Using the quadratic formula, we obtain that the two solutions are $\frac{-3 \pm i\sqrt{4(7)(k)-9}}{14}$, so we have:

 

$4(7)(k)-9=271$

$28k-9=271$

$28k=280$

$\boxed{k=10}$

RiemannIntegralzzz Apr 6, 2021

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