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Let a and b be real numbers such that a+b=-1 and a-b=2. Compute a^2-b^2.

 Jun 23, 2022

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 #1
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Note that \(a^2 - b^2 = (a+b)(a-b)\).

 

Can you take it from here?

 Jun 23, 2022
 #1
avatar+2448 
0
Best Answer

Note that \(a^2 - b^2 = (a+b)(a-b)\).

 

Can you take it from here?

BuilderBoi Jun 23, 2022

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