If (2x+5)(x-3)=14 + x^2 - 7x, find the sum of the possible values of x.
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\((2x+5)(x-3)=14 + x^2 - 7x\\ 2x^2-6x+5x-15-14-x^2+7x=0\\ x^2+6x-29=0\)
\(x=3\pm \sqrt{9+29}\\ x=3\pm \sqrt{38}\)
\(x_1=3+\sqrt{38}\\ x_2=3-\sqrt{38}\)
\(x_1+x_2=6\)
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