Given $x\neq0$, find the positive value of b such that the equation \(\frac{3}{x} + x = b\) will have exactly one solution.
3/x + x = b multiply through by x and rearrange
x^2 -bx + 3 = 0
If we have one solution then the discriminant = 0 .....so.....
b^2 - 4*3*1 = 0
b^2 - 12 = 0
b = sqrt (12) = 2sqrt (3)
