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Find the smallest positive integer b for which x^2+bx+2018 factors into a product of two binomials, each having integer coefficients.

 May 30, 2021
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Factors of 2018   are  1   2    1009   and   2018     and the negatives

(x+2)(x+1009)   would result in b = 1011    the smallest positive

 

 

 

 

(x-2018)(x-1)      would result in b = - 2019   for the overall smallest integer (but negative)

 May 30, 2021

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