Find the smallest positive integer b for which x^2+bx+2018 factors into a product of two binomials, each having integer coefficients.
+36914 Factors of 2018 are 1 2 1009 and 2018 and the negatives
(x+2)(x+1009) would result in b = 1011 the smallest positive
(x-2018)(x-1) would result in b = - 2019 for the overall smallest integer (but negative)
