The solutions of x(x - 3) = 2 may be expressed in the form (a + sqrt(b))/c and (a - sqrt(b))/c, where a, b, and c are prime numbers. Find a + b + c.
Expand to get
x^2 -3x -2 = 0 Use quadratic fromula a = 1 b = -3 c = -2
\(x = {-(-3) \pm \sqrt{(-3^2)^2-4(1)(-2)} \over 2(1)}\) to get your answer.............
Expand to get
x^2 -3x -2 = 0 Use quadratic fromula a = 1 b = -3 c = -2
\(x = {-(-3) \pm \sqrt{(-3^2)^2-4(1)(-2)} \over 2(1)}\) to get your answer.............