Simplify $\frac{\sqrt{72}}{\sqrt{25}}$. Your answer should have an integer denominator.
$\sqrt{25}=5$
$\sqrt{72}=\sqrt{4\cdot9\cdot2}=6\sqrt2$
so $\frac{\sqrt{72}}{\sqrt{25}}=\boxed{\dfrac{6\sqrt2}{5}}$
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