Suppose r and s are the roots of the equation 3x^2 + 9x + 15 = 2x^2 + 8x - 17. Find (r+1)(s+1)

Guest Jan 1, 2023

#2**+3 **

We have:

\(3x^2+9x+15=2x^2+8x-17\)

Start off by simplifying.

\(x^2+x+32=0\)

We want to find (r+1)(s+1) = rs+r+s+1

We apply Vieta's formula:

rs = 32

r+s = -1

32-1+1 =** 32**

hairyberry Jan 1, 2023