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Suppose r and s are the roots of the equation 3x^2 + 9x + 15 = 2x^2 + 8x - 17. Find (r+1)(s+1)

 Jan 1, 2023
 #1
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(r + 1)(s + 1) = -16.

 Jan 1, 2023
 #2
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We have:

\(3x^2+9x+15=2x^2+8x-17\)

Start off by simplifying.

\(x^2+x+32=0\)

We want to find (r+1)(s+1) = rs+r+s+1

We apply Vieta's formula:

rs = 32

r+s = -1

32-1+1 = 32

 Jan 1, 2023

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