The arithmetic mean of 23, 16, 30, 33 and two other numbers that differ by 2 is 27. If the smallest of these 6 numbers is discarded, find the arithmetic mean of the remaining 5 numbers.
( 23 + 16 + 30 + 33 + x + x + 2) / 6 = 27
(104 + 2x) = 27*6
104 + 2x = 162
2x = 162 - 104
2x = 58
x = 58 / 2 = 29 x + 2 = 31
So.......16 is discarded
(23 + 29 + 30 + 31 + 33) / 5 = 146 / 5 = 29.2 = new mean
