A parabola with equation y=ax^2+bx+c contains the points (-3,3), (1,3), and (0,0). Find the value of 100a+10b+c.
+36 Plug in all of the points and create 3 seperate equations:
#1: 3 = a(-3)^2 + b(-3) + c
#2: 3 = a(1)^2 + b(1) + c
#3: 0 = a(0)^2 + b(0) + c
You can use the last equation to get the value of c, which is 0. You can then use substitution or elimination, whichever you choose, to simplify and solve for a and b. Hope this helps!
Let me know if I did anything wrong!
