Help as soon as you can, not in a hurry.

1)  Note that  25^(17/x)  = ( 5^2)^( 17/x)  =  5^(34/ x)

25^(-2)  =  5^(48/x)  / [ 5^(26/x) * 5^(34/x)  ]

(5^2)^(-2)   =  5^(48/x)  /  [ 5^(60/x)]

5^(-4)  =  5^(48/x - 60/x)

5^(-4)  = 5^(-12/x)

We have the same bases, so we can solve for the exponents

-4  =  -12 /x  multiply through by x

-4x  = -12   divide both sides by -4

x  = 3