For what negative value of k is there exactly one solution to the system of equations \(\begin{align*} y &= 2x^2 + kx + 6 \\ y &= -x + 4? \end{align*}\)

Guest Oct 4, 2019

#1**+2 **

Substitute and simplify

2x^{2 }+ (k+1)x + 2

There is exactly one solution when the discriminate is equal to 0.

That is my hint and I will let you solve.

CalculatorUser Oct 4, 2019