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The domain of the function,\(r(x) = \frac{x^2}{1-x}\)  is \((-\infty,1)\cup(1,\infty)\). What is the range?

 Nov 12, 2022
 #1
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The range is (-inf,-1) U [0,inf).

 Nov 12, 2022
 #2
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Thanks for the response. However, it says that it is wrong.

Guest Nov 12, 2022
 #3
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Graphing it on desmos, the interval from (-4,0) is entirely skipped, so the range is. \((-\infty, -4] \cup[0,\infty)\)

 

hope this helped smiley

 Nov 13, 2022

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