The domain of the function,\(r(x) = \frac{x^2}{1-x}\) is \((-\infty,1)\cup(1,\infty)\). What is the range?

Guest Nov 12, 2022

#3**+1 **

Graphing it on desmos, the interval from (-4,0) is entirely skipped, so the range is. \((-\infty, -4] \cup[0,\infty)\)

hope this helped

guestperson Nov 13, 2022