HELP asAP plz

Question

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In the diagram below, \(\overline{MN}\) is a diameter of the circle. Find \(\angle XYZ\) , in degrees.

Guest Apr 9, 2020

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Best Answer

Angle(M) = ½·arc(ZN) ---> Angle(M) = 40^o

Angle(N) = ½·arc(XM) ---> Angle(N) = 17.5^o

In Triangle(MYN), Angle(MYN) = 180^o - 40^o - 17.5^o = 122.5^o.

Angle(MYN) and Angle(XYZ) ae vetical angles; therefore, Angl(XYZ) = ....

geno3141 Apr 9, 2020

geno3141 · Answer 1 · 2020-04-09T05:39:50

Angle(M) = ½·arc(ZN) ---> Angle(M) = 40^o

Angle(N) = ½·arc(XM) ---> Angle(N) = 17.5^o

In Triangle(MYN), Angle(MYN) = 180^o - 40^o - 17.5^o = 122.5^o.

Angle(MYN) and Angle(XYZ) ae vetical angles; therefore, Angl(XYZ) = ....