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In the diagram below, \(\overline{MN}\) is a diameter of the circle. Find \(\angle XYZ\) , in degrees.

 

 Apr 9, 2020

Best Answer 

 #1
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Angle(M) = ½·arc(ZN)   --->   Angle(M)  =  40o 

Angle(N)  = ½·arc(XM)   --->   Angle(N)  =  17.5o  

In Triangle(MYN), Angle(MYN)  =  180o -  40o -  17.5o  = 122.5o.

Angle(MYN) and Angle(XYZ) ae vetical angles; therefore, Angl(XYZ)  =  ....

 Apr 9, 2020
 #1
avatar+20981 
+1
Best Answer

Angle(M) = ½·arc(ZN)   --->   Angle(M)  =  40o 

Angle(N)  = ½·arc(XM)   --->   Angle(N)  =  17.5o  

In Triangle(MYN), Angle(MYN)  =  180o -  40o -  17.5o  = 122.5o.

Angle(MYN) and Angle(XYZ) ae vetical angles; therefore, Angl(XYZ)  =  ....

geno3141 Apr 9, 2020

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