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When g(x) is divided by x^2-x-6 , the remainder is x+5.

What is the value of g(3)?

 May 28, 2020
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When g(x) is divided by x^2-x-6 , the remainder is x+5.

What is the value of g(3)?

 

You can write g(x) = p(x)*(x^2-x-6) + x+5   where p(x) is some other polynomial.

 

When x = 3   x^2-x-6 = 0, so all that is left of g(3) is 3 + 5.  i.e. g(3) = 8

 May 28, 2020

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