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In right triangle \(DEF\), we have \(\angle D = 25^\circ\)\(\angle E = 90^\circ\), and \(EF = 9\). Find \(DE\) to the nearest tenth. You may use a calculator for this problem.

 Feb 24, 2021
 #1
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 I think its 40 I dunno

 Feb 24, 2021
 #2
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Let x = side DE


\(Tan(25) = \frac{9}{x} \)

\(\frac{9}{x} ≈ 0.466 \)

\(x ≈ \frac{9}{0.466}\)

\(x ≈ 19.3\)

 Feb 26, 2021
 #3
avatar+294 
+3

Thanks!

calvinbun  Feb 27, 2021

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