In right triangle \(DEF\), we have \(\angle D = 25^\circ\), \(\angle E = 90^\circ\), and \(EF = 9\). Find \(DE\) to the nearest tenth. You may use a calculator for this problem.
I think its 40 I dunno
Let x = side DE
\(Tan(25) = \frac{9}{x} \)
\(\frac{9}{x} ≈ 0.466 \)
\(x ≈ \frac{9}{0.466}\)
\(x ≈ 19.3\)
Thanks!
+379 
