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In triangle ABC, angle bisectors AD, BE, and CF meet at I. If DI = 3, BD = 4, and BI = 5, then compute the area of triangle ABC.

 

Please explain your answer!!! THANK YOU!!!

 Nov 14, 2020
 #1
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See https://web2.0calc.com/questions/help-is-needed_5.

 Nov 14, 2020
 #2
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Triangle ABC is an isosceles triangle with a base of 8 units.

 

angle (B) = 2(arctan3/4)

 

angle (A/2) = 90 - angle (B)

 

height AD = BD / tan(A/2)

 

area = BD * AD = 54.85714289 units squared

 Nov 14, 2020

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