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Let line L1 be the graph of 5x + 8y = -9. Line L2 is perpendicular to line L1 and passes through the point (10,10). If line L2 is the graph of the equation y=mx +b, then find m+b.

 Nov 1, 2020
 #1
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By using point-slope form, we get that m + b = -7/3.

 Nov 1, 2020
 #2
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Let line L1 be the graph of 5x + 8y = -9. Line L2 is perpendicular to line L1 and passes through the point (10,10). If line L2 is the graph of the equation y=mx +b, then find m+b.

 

Hello Guest!

 

\(L1\\ 5x + 8y = -9\\ y=-\frac{5}{8}x-\frac{9}{8}\)

 

\(\color{blue}m=-\frac{1}{-\frac{5}{8}}\\ \color{blue}m=1.6\)

 

\(L2\\ y=mx +b\\ P(10,10)\\ 0=1.6\cdot 10+b\\ b=10-1.6\cdot 10\)

\(\color{blue}b=-6\\ y=1.6x-6\)

 

\(m+b=-4.4\)

laugh  !

 Nov 1, 2020
edited by asinus  Nov 1, 2020

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