\(\frac{6}{2}-\frac{5n}{4n^2-22n-12}\)
All I know is 6/2 is reduced to 3/1 so it ends up being 3-5n/4n^2-22n-12
OK...you got the first part
Note that the second denominator can be factored as
2 ( 2n^2 - 11n - 6) = 2 (2n + 1) (n - 6)
So...we have
3 5n
__ - _____________
1 4n^2 - 22n - 12
Cross- multiply in this order
3 (4n^2 - 22n - 12) - 1 * 5n
12n^2 - 66n - 36 - 5n
12n^2 - 71n - 36
The product of the denominators = 4n^2 - 22n - 12
So we are left with
12n^2 - 71n - 36
_____________ (1)
4n^2 - 22n - 12
Note RP.....the top polynomial can't be factored
You COULD factor the bottom as
2 (2n^2 - 11n - 6) = 2(2n + 1) ( n - 6)
So (1) could be expressed as
12n^2 - 71n - 36
______________
2 (2n + 1) (n - 6)