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Simplify the top

Cross-multiply   and keep the same sign between the terms as we have between the fractions

5a + 4a^2

Take the product of the denominators

4 * 5  =  20

So.....we have

[ 5a + 4a^2]              25

__________  ÷       ___

       20                      1

Just like "regular" fractions......Invert the second fraction and multiply

[ 5a + 4a^2 ]                  1

___________      x      _____

     20                            25

5a  +  4a^2

_________

   500

I agree with @CPhill! We have \(\frac{5a+4a^2}{20}\) after joining \(\frac{a}{4}+\frac{a^2}{5}\), together. Now. we have \(\frac{\frac{5a+4a^2}{20}}{25}\) which is \(\frac{5a+4a^2}{20\cdot \:25}\), or our final answer of \(\frac{5a+4a^2}{500}.\)