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In the diagram below, quadrilateral BAED is a parallelogram, and BD = BC. If angle DBC = 28˚, then find angle EAB, in degrees.

 

 


 

 Aug 26, 2020
 #1
avatar+1042 
+1

We see that since BDC is an iscosoles triangle, so therefore angle BDC = angle BCD = x.

 

28 + 2x = 180

2x = 152

x = 76

 

From here, we see that angle EDB = 180 - 76 = 104

 

Since we are talking about a parallelogram, angle EDB = angle EAB = 104

 

:)

 Aug 26, 2020
edited by ilorty  Aug 26, 2020
edited by ilorty  Aug 26, 2020
 #2
avatar+1322 
0

140 ???cheeky

Dragan  Aug 26, 2020
 #3
avatar+1042 
+1

Im sorry, but what do you mean? Thanks!

 

:)

ilorty  Aug 26, 2020
 #4
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Your final answer is correct, but 180-76 is not 140  smiley

 Aug 26, 2020
 #5
avatar+1042 
+1

Oops!

ilorty  Aug 26, 2020

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