In the diagram below, quadrilateral BAED is a parallelogram, and BD = BC. If angle DBC = 28˚, then find angle EAB, in degrees.
We see that since BDC is an iscosoles triangle, so therefore angle BDC = angle BCD = x.
28 + 2x = 180
2x = 152
x = 76
From here, we see that angle EDB = 180 - 76 = 104
Since we are talking about a parallelogram, angle EDB = angle EAB = 104
:)
140 ???
Im sorry, but what do you mean? Thanks!
Your final answer is correct, but 180-76 is not 140
Oops!
