In the diagram below, quadrilateral BAED is a parallelogram, and BD = BC. If angle DBC = 28˚, then find angle EAB, in degrees.

We see that since BDC is an iscosoles triangle, so therefore angle BDC = angle BCD = x.

28 + 2x = 180

2x = 152

x = 76

From here, we see that angle EDB = 180 - 76 = 104

Since we are talking about a parallelogram, angle EDB = angle EAB = 104

:)

140 ???

Im sorry, but what do you mean? Thanks!

Your final answer is correct, but 180-76 is not 140

Oops!