Find the smallest positive N such that
\(\begin{align*} N &\equiv 3 \pmod{4}, \\ N &\equiv 2 \pmod{5}, \\ N &\equiv 6 \pmod{7}. \end{align*}\)
N = 27 mod[LCM(4, 5, 7)]
N = 27 mod 140
N =140n +27, where n=0, 1, 2, 3.......etc.
So, the smallest N = 27.
