We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
153
1
avatar

We roll a fair 6-sided die 5 times. What is the probability that we get a 6 in at most 2 of the rolls?

 Jul 4, 2019
 #1
avatar+104025 
+1

P(rolling no 6's)  =  (5/6)^5

P(rolling one 6)  =  C(5,1) (1/6)(5/6)^4

P(rolling two 6's)  = C(5,2) (1/6)^2 (5/6)^3

 

So.....the probability is

 

(5/6)^5 + C(5,1)(1/6)(5/6)^4  + C(5,2) (1/6)^2 (5/6)^3  =  625/648 ≈  .964  ≈  96.4%

 

cool cool cool 

 Jul 4, 2019

15 Online Users

avatar
avatar
avatar