Find the number of ordered pairs (a, b) of integers such that
\(\[\frac{a + 2}{a + 5} = \frac{b}{4}.\]\)
(a + 2) / ( a + 5) = b /4
4 (a + 2) = b ( a + 5)
4a + 8 = ab + 5b
b ( a + 5) = 4a + 8
b = ( 4a + 8) / (a + 5)
b = 4 ( a + 2) / (a + 5)
b will never be less than 5 when a approaches negative infinity
b will never be more than 3 when a approaches positive infinity
a b
-17 5
-11 6
-8 8
-7 10
-6 16
-4 -8
-3 -2
-2 0
-1 1
1 2
7 3