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http://web2.0calc.com/img/upload/02ca0f606be8be8a9a85e138/650344d1-2e91-4f78-9d38-aa4dbd8988a3.png

 Jan 18, 2018
edited by Guest  Jan 18, 2018
 #1
avatar+1442 
+1

The mathematician solves 112 problems that day.

 

We can rewrite the equation as (3p+7)(t-4) = 2tp, then we can solve for t with 4*(3-(14/p+7)).  The expression (14/p+7) can only be 1, which results in a value of 7 for p.  We can then solve the problem easily: (3*7 + 7)(8-4) = 28*4 = 112.

 Jan 18, 2018
edited by AnonymousConfusedGuy  Jan 18, 2018
 #2
avatar+99117 
0

Just give us the address of the old question please.

 

NOT the address of the screen capture!

 Jan 18, 2018
 #3
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0

The questions second half is getting cut off for a unknown reason.

Guest Jan 18, 2018
 #4
avatar+98005 
+2

Number of problems normally answered per day   is

 

p * t

 

So......when he drinks coffee, he solves

 

(3p + 7)  (t - 4)  problems....and this is twice the number he normally answers...so...

 

(3p + 7) (t - 4)    =   2p*t

 

3pt  +  7t   -  12p  -  28  =  2pt

 

pt  +  7t  -  12p  -  28  =  0

 

We have an equation with two unknowns....so....there will possibly be more than one solution

 

WolframAlpha shows that the (possible) feasible solutions are

 

p = 1     t  = 5   =    5 problems on a regular day

p = 7     t  = 8  =    56 problems on a normal day

 

 

So as a check

 

(3*1 + 7)(5 - 4)  = (2)(1*5)  ??

(10)(1)  = 10  is true

 

(3*7 + 7) (8 - 4)  = (2)(7*8)  ???

(28) (4)  = 112

112 =  112    is also true

 

So.......the number of problems that he answers when he drinks coffee is either

(3)(1) + 7    =  10  problems per day

or

(3)(7) + 7  =   112 problems per day

 

 

 

 

cool cool cool

 Jan 19, 2018
edited by CPhill  Jan 19, 2018

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