http://web2.0calc.com/img/upload/02ca0f606be8be8a9a85e138/650344d1-2e91-4f78-9d38-aa4dbd8988a3.png
The mathematician solves 112 problems that day.
We can rewrite the equation as (3p+7)(t-4) = 2tp, then we can solve for t with 4*(3-(14/p+7)). The expression (14/p+7) can only be 1, which results in a value of 7 for p. We can then solve the problem easily: (3*7 + 7)(8-4) = 28*4 = 112.
Just give us the address of the old question please.
NOT the address of the screen capture!
Number of problems normally answered per day is
p * t
So......when he drinks coffee, he solves
(3p + 7) (t - 4) problems....and this is twice the number he normally answers...so...
(3p + 7) (t - 4) = 2p*t
3pt + 7t - 12p - 28 = 2pt
pt + 7t - 12p - 28 = 0
We have an equation with two unknowns....so....there will possibly be more than one solution
WolframAlpha shows that the (possible) feasible solutions are
p = 1 t = 5 = 5 problems on a regular day
p = 7 t = 8 = 56 problems on a normal day
So as a check
(3*1 + 7)(5 - 4) = (2)(1*5) ??
(10)(1) = 10 is true
(3*7 + 7) (8 - 4) = (2)(7*8) ???
(28) (4) = 112
112 = 112 is also true
So.......the number of problems that he answers when he drinks coffee is either
(3)(1) + 7 = 10 problems per day
or
(3)(7) + 7 = 112 problems per day