http://web2.0calc.com/img/upload/02ca0f606be8be8a9a85e138/650344d1-2e91-4f78-9d38-aa4dbd8988a3.png

Guest Jan 18, 2018

edited by
Guest
Jan 18, 2018

#1**+1 **

The mathematician solves 112 problems that day.

We can rewrite the equation as (3p+7)(t-4) = 2tp, then we can solve for t with 4*(3-(14/p+7)). The expression (14/p+7) can only be 1, which results in a value of 7 for p. We can then solve the problem easily: (3*7 + 7)(8-4) = 28*4 = 112.

AnonymousConfusedGuy
Jan 18, 2018

#2**0 **

Just give us the address of the old question please.

NOT the address of the screen capture!

Melody
Jan 18, 2018

#4**+2 **

Number of problems normally answered per day is

p * t

So......when he drinks coffee, he solves

(3p + 7) (t - 4) problems....and this is twice the number he normally answers...so...

(3p + 7) (t - 4) = 2p*t

3pt + 7t - 12p - 28 = 2pt

pt + 7t - 12p - 28 = 0

We have an equation with two unknowns....so....there will possibly be more than one solution

WolframAlpha shows that the (possible) feasible solutions are

p = 1 t = 5 = 5 problems on a regular day

p = 7 t = 8 = 56 problems on a normal day

So as a check

(3*1 + 7)(5 - 4) = (2)(1*5) ??

(10)(1) = 10 is true

(3*7 + 7) (8 - 4) = (2)(7*8) ???

(28) (4) = 112

112 = 112 is also true

So.......the number of problems that he answers when he drinks coffee is either

(3)(1) + 7 = 10 problems per day

or

(3)(7) + 7 = 112 problems per day

CPhill
Jan 19, 2018