The equation $y = -4.9t^2 - 3.5t + 2.4$ relates the height $y$ (in meters) to the elapsed time $t$ (in seconds) for a ball thrown downward at 3.5 meters per second from a height of 2.4 meters from the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest hundredth.

Guest Oct 30, 2020

#1**+1 **

height will be zero when it hits the ground

0 = -4.9t^2-3.5t+ 2.4 use Quadratic formula to find t = .429 seconds

ElectricPavlov Oct 30, 2020