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#3**+8 **

We have ..... h(x) = x^{2} + 4

And I'm not sure, but I think this person might be wanting to evalute the composite function (h º h)(a)

This says to put "a" into f(x), and then put* that* result

So we have......

h(a) = a^{2} + 4 and "plugging" this result back into h(x), we have

h(a^{2} + 4) = (a^{2} + 4)^{2} + 4 = a^{4} + 8a^{2} + 20

And that's (h º h)(a) ...... (If that was the original intent !! )

CPhill Sep 26, 2014

#1**+3 **

Ok wow thats tough I dont think thats possible. So no, this is not a helpful answer to your desperate plea. Sorry...

Guest Sep 25, 2014

#2**+8 **

I am really guessing here - would someone like to verify please.

Plus I do not know how to use the notation properly.

h(x)=x^2+4 (h∘h)(a)

$$\\(x^2+4)^2+4 \\

$sub in a$\\

=(a^2+4)^2+4\\

=a^4+8a^2+16+4\\

=a^4+8a^2+20\\$$

Melody Sep 26, 2014

#3**+8 **

Best Answer

We have ..... h(x) = x^{2} + 4

And I'm not sure, but I think this person might be wanting to evalute the composite function (h º h)(a)

This says to put "a" into f(x), and then put* that* result

So we have......

h(a) = a^{2} + 4 and "plugging" this result back into h(x), we have

h(a^{2} + 4) = (a^{2} + 4)^{2} + 4 = a^{4} + 8a^{2} + 20

And that's (h º h)(a) ...... (If that was the original intent !! )

CPhill Sep 26, 2014