Take all 5 = 1 set
Include 5 and select any 3 of the other 4 elements = C(4,3) = 4 sets
Include 5 and select any 2 of the other 4 elements = C(4,2) = 6 sets
Include 5 and select any 1 of the other 4 elements = C(4,1) = 4 sets
Include 5 only = 1 set
So
1 + 4 + 6 + 4 + 1 = 16 sets