Find the value of n if (1 / 27^-4 * 9)= 81^n
Find the value of n.
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\(\frac{1}{27^{-4}}\cdot 9=81^n\\ 27^4\cdot9=81^n\\ 3^{3\cdot 4}\cdot 3^2=3^{4n}\\ 3^{3\cdot 4+2}=3^{4n}\\ 3\cdot 4+2=4n\\ 4n=14\)
\(n=3.5\)
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Thank you so much!
Please help me! x2 – 4x ≤ 5 Happy wheels
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